Choosing a non defective bolt from a box containg bolts
Problem 3
Solution
Total number of bolts
= 400
Experiment :
Choosing a bolt from the 400 bolts in the box
Total Number of Possible Choices
= Number of ways in which a bolt can be chosen from among the 400 bolts in the box
⇒ n | = | 400C1 | ||
= |
| |||
= | 400 |
Let
A : the event of choosing a non defective bolt
For Event A
= 20
Number of non defective bolts
= Total number of bolts in the box − Number of defective bolts in the box
= 400 − 20
= 380
Favorable (non defective) | Unfavorable (Others) | Total | |
---|---|---|---|
Available | 380 | 20 | 400 |
To Choose | 1 | 0 | 1 |
Choices | 380C1 | 20C0 | 400C1 |
Number of Favorable Choices
= Number of ways in which a non defective bolt can be selected from the total 380 favorable bolts
⇒ mA | = | 380C1 | ||
= |
| |||
= | 380 |
Probability of choosing a non defective bolt
⇒ Probability of occurrence of Event A
= |
|
⇒ P(A) | = |
| ||
= |
| |||
= |
|
Odds
= Total Number of possible choices − Number of Favorable choices
⇒ mAc | = | n − mA |
= | 88 − 8 | |
= | 80 |
in favor
Odds in Favor of choosing a non defective bolt⇒ Odds in Favor of Event A
= Number of Favorable Choices : Number of Unfavorable Choices
= mA : mAc
= 380 : 20
= 19 : 1
against
Odds against choosing a non defective bolt⇒ Odds against Event A
= Number of Unfavorable Choices : Number of Favorable Choices
= mAc : mA
= 20 : 380
= 1 : 19