Theory of Expectation :: Problems on Tossing Coins : Probability Distribution

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Three coins, whose faces are marked 1 and 2, are tossed what is the expectation of total value of numbers on their faces?

Net Answers :
[Expectation: 3 ; Variance:0.5]

Solution  
 

Let "x" indicate the total value of the numbers appearing on the face of the coins

[Since you are required to find the expectation of the total value of numbers, the variable would represent the total of the numbers appearing on the face of the coins.]

The total value of the numbers appearing on the face of the coins would be

  • 4 if both the coins show up 2
  • 3 if one coin shows up 2 and the other 1
  • 2 if both the coins show up 1

⇒ The values carried by the variable ("x") would be either 1, 3, or 4
⇒ "X" is a discrete random variable with range = {1, 3, 4}

"X" represents the random variable and P(X = x) represents the probability that the value within the range of the random variable is a specified value of "x"

In the experiment of tossing the 2 coins

Total no. of possible choices = 2 × 2
= 4

Let "O" represent the coin showing up 1 and "T" represent the coin showing up 2.

Probabilty that the 2 coins would show up

  • Two TWO's =
    No. of favorable choices
    Total no. of possible choices

    ⇒ P(TT) =
    1
    4

    For the two letter word "TT"

    No. of letters

    in total = 2 ⇒ n = 2
    of the first kind = 2 {T, T} ⇒ a = 2
    all of which are different = 0 ⇒ x = 0

    No. of favorable choices = No. of ways in which the two
    letters of the word TT can be permuted.
    =
    n!
    a!
    =
    2!
    2!
    = 1

  • A "ONE" and a "TWO" =
    No. of favorable choices
    Total no. of possible choices

    ⇒ P(OT) =
    2
    4

    For the two letter word "OT"

    No. of letters

    in total = 2 ⇒ n = 2
    all of which are different = 2 {O, T} ⇒ x = 2

    No. of favorable choices = No. of ways in which the twoe
    letters of the word OT can be permuted.
    = n!
    = 2!
    = 2 × 1
    = 2

  • Two ONE's =
    No. of favorable choices
    Total no. of possible choices

    ⇒ P(OO) =
    1
    4

    For the two letter word "OO"

    No. of letters

    in total = 2 ⇒ n = 2
    of the first kind = 2 {O, O} ⇒ a = 2
    all of which are different = 0 {} ⇒ x = 0

    No. of favorable choices = No. of ways in which the two
    letters of the word OO can be permuted.
    =
    n!
    a!
    =
    2!
    2!
    = 1

    Therefore, probability that the total value of the numbers on the faces of the two coins is

  • 4 ⇒ P(X = 4) =
    1
    4
  • 3 ⇒ P(X = 3) =
    2
    4
    (Or)
    1
    2
  • 2 ⇒ P(X = 2) =
    1
    4

    The probabilty distribution of "x" would be
    x 2 3 4
    P(X = x)
    1
    4
    2
    4
    1
    4

    Calculations for Mean and Standard Deviations

    x P (X = x) px
    [x × P (X = x)]
    x2 px2
    [x2 × P (X = x)]
    2
    1
    4
    2
    4
    4
    4
    4
    3
    2
    4
    6
    4
    9
    18
    4
    4
    1
    4
    4
    4
    16
    16
    4
    Total 1
    12
    4
    38
    4
    = 3 = 9.5

    Expected total value of the numbers on the faces


    ⇒ Expectation of "x"
    ⇒ E (x) = Σ px
    = 3
    Variance of the total value of the numbers on the faces
    ⇒ var (x) = E (x2) − (E(x))2
    ⇒ var (x) = Σ px2 − (Σ px)2
    = 9.5 − (3)2
    = 9.5 − 9
    = 0.5
    Standard Deviation of the total value of the numbers on the faces
    ⇒ SD (x) = + Var (x)
    = + 0.5
    = + 0.707

    Credit : Vijayalakshmi Desu

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