# Choosing One/Single Coin Dice/Die Card Number Ticket Ball Member Student - Probability

# Single Coin

⇒ There are two possible outcomes or choices in the experiment of tossing a coin, which are equally likely, mutually exclusive and exhaustive.

⇒ For the experiment of tossing a coin, the total number of possible choices is 2.

**⇒ n = 2**

# Single Dice

When a dice or die is tossed/rolled/thrown, one of these faces appears which implies that one of the six numbers appear on the face of the dice/die.

There is an equally likely chance for all these six faces i.e. the six numbers to appear. Moreover, only one of these will appear on a single throw.

⇒ There are six possible outcomes or choices in the experiment of tossing/rolling/throwing a dice/die, which are equally likely, mutually exclusive and exhaustive.

⇒ For the experiment of tossing/throwing/rollling a dice/die, the total number of possible choices is 6.

**⇒ n = 6**

# Single Card

- Spades ♠
- Clubs ♣
- Diamonds ♦
- Hearts ♥

Two of the sets are colored red and two others black i.e. there are

- 26 (13 × 2) red cards
- 26 (13 × 2) black cards

Each set has 13 cards which are marked "A", "2", "4", "5", "6", "7", "8", "9", "10", "K", "Q", "J".

- "A" represents the number "ONE" and is also called "Ace".
- "K" represents kings and is marked with a picture indicative of a king.
- "Q" represents Queen and is marked with a picture indicative of a Queen.
- "J" represents a young prince and is marked with a picture indicative of a Young Prince. It is also called a "Jack" or a "Knave".

Spades (♠) | Clubs (♣) | Diamonds (♦) | Hearts (♥) | Total |
---|---|---|---|---|

A 2 3 4 5 6 7 8 9 10 K Q J | A 2 3 4 5 6 7 8 9 10 K Q J | A 2 3 4 5 6 7 8 9 10 K Q J | A 2 3 4 5 6 7 8 9 10 K Q J | 4 4 4 4 4 4 4 4 4 4 4 4 4 |

13 | 13 | 13 | 13 | 52 |

## Well shuffled Cards

Well shuffled cards implies cards that are mixed up well.### shuffle

- Mix so as to make a random order or arrangement.

## Experiment

The experiment that we identify for the purpose of calculating probability in case of drawing cards would vary depending on the number of cards being drawn at a time.Drawing one card is an experiment different from the experiment of drawing two cards. As the number of cards drawn vary, the experiment varies.

## Experiment of drawing a single card

For this explanation we will consider only the experiment of drawing a single card.**In the experiment of drawing a card from a pack of 52 cards,**

The total number of possible choices

= | Number of ways in which one card can be drawn from the total 52 cards |

⇒ n | = | ^{52}C_{1}Number of combinations of "n" different things "r" at a time. | ||

= |
| |||

= | 52 |

By sheer logic we will be able to say that the card drawn may be any of the 52 cards which creates the 52 different possibilities or choices. These possibilities form the total number of possible choices for the experiment of drawing a card from the pack. The formula/expression given above would help us in finding the number of possible choices whatever may be the number of cards drawn.

## Favorable Choices

The number of favorable choices for drawing a required card can also be calculated by a similar logic.To enable the calculation of the number of favorable choices,

- Divide the total 52 cards into two groups.
- One group consisting of all the cards which are favorable for the occurrence of the given event
- The second group consisting of all the other cards

### Examples

**Number of favorable choices for drawing a card which is red.**Favorable

[Red Cards]Others Total Available 26 26 52 To Choose 1 0 1 Choices ^{26}C_{1}^{26}C_{0}^{52}C_{1}The number of favorable choices

= Number of ways in which one card which is a red card can be drawn from the total 26 cards ⇒ **m**= ^{26}C_{1}Number of combinations of "n" different things "r" at a time.

= 26 1 = 26 **Number of favorable choices for drawing a card which is a spades or a king**Favorable

[Spades + Other Kings]Others Total Available 16 (13 + 3) 36 52 To Choose 1 0 1 Choices ^{16}C_{1}^{36}C_{0}^{52}C_{1}There are 13 spades which includes a king in it. Therefore, we consider the other 3 kings also to give us the set of cards from which any card can appear to make our effort a success.

The number of favorable choices

= Number of ways in which one card which is either a spade or a king can be drawn from the total 16 cards ⇒ **m**= ^{16}C_{1}Number of combinations of "n" different things "r" at a time.

= 16 1 = 16

Notice that we can find the total number of possible choices for the experiment as well as the number of favorable choices for the event from the table.

## Note

The above procedure of building up a table for finding out the number of favorable choices would help a lot in solving majority of the problems based on the mathematical definition of probability.# Picking up One entity from a group

Some Examples

- Choosing a Number from a group/set of Numbers
- Choosing a Coloured/Colored ball from a number of balls
- Choosing a ticket from tickets marked with numbers
- Choosing a page from a book whose pages are numbered
- Choosing a person from among a group of persons

## Build a Working Table

Build a table similar to the one used in case of a card drawn from a pack of cards.- Divide the total entities into two groups.
- One group consisting of all the entities which are favorable for the occurrence of the given event
- The second group consisting of all the other entities

Favorable | Others | Total | |
---|---|---|---|

Available | a | b | a+b |

To Choose | 1 | 0 | 1 |

Choices | ^{a}C_{1} | ^{b}C_{0} | ^{(a+b)}C_{1} |